分解质因数
发布日期:2021-05-15 08:58:18 浏览次数:21 分类:精选文章

本文共 1568 字,大约阅读时间需要 5 分钟。

Here's an optimized version of the code along with the step-by-step explanation:

#include 
#include
int main() {
int n, a = 2;
std::cin >> n;
while (n != 1) {
if (n % a == 0) {
std::cout << a << " ";
n /= a;
} else {
if (a == 2) {
a = 3;
} else {
a += 2; // Check only odd numbers after 2
}
if (a * a > n) {
std::cout << n << " ";
n = 1;
}
}
}
return 0;
}

Explanation:

  • Initialization:

    • Read the integer n from the input.
    • Initialize a to 2, the smallest prime number.
  • While Loop:

    • Continue the loop until n is reduced to 1.
    • This ensures all factors are processed until n is completely divided.
  • Check Divisibility:

    • For each a, check if n is divisible by a.
    • If yes, print a and divide n by a. Continue this to factorize n completely.
  • Handle Even and Odd Numbers:

    • After checking for 2, handle all subsequent factors by incrementing a by 2. This optimizes by skipping even numbers, reducing the number of checks.
  • Optimization Check:

    • If a squared exceeds n, it means n has no more factors apart from itself. If n is greater than 1, print it as a prime factor.
    • Set n to 1 to terminate the loop.
  • Termination:

    • Once n becomes 1, the loop exits, and the function returns 0, indicating all prime factors have been processed.
  • This version optimizes the code by minimizing unnecessary checks and improving efficiency, ensuring it's both effective and easy to understand.

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