
Leetcode No.104 Maximum Depth of Binary Tree 遍历二叉树的深度
发布日期:2021-05-07 23:35:04
浏览次数:16
分类:精选文章
本文共 1303 字,大约阅读时间需要 4 分钟。
Given a binary tree, find its maximum depth.
The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
注:题库和图片转自 www.leetcode.com ,所有权归www.leetcode.com仅供交流学习使用,不得用于商业用途
-----------------------------------------------------------------------------------------------------
我的解法:/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */class Solution {public: int maxDepth(TreeNode* root) { int currentDepth = 0; maxDep = 0; if(root != NULL) { travelBinaryTree(root, currentDepth); } return maxDep; }private: int maxDep; void travelBinaryTree(TreeNode* node, int depth) { depth++; maxDep = (depth > maxDep) ? depth : maxDep; if(node->left) travelBinaryTree(node->left, depth); if(node->right) travelBinaryTree(node->right, depth); }};虽然结果正确,看了一下bbs上的讨论,感觉算法虽然不复杂但是太多代码冗余,leetcode上比较精简的一种解法
class Solution {public: int maxDepth(TreeNode* root) { if (!root) return 0; return 1 + max(maxDepth(root->right), maxDepth(root->left)); }};利用return的时候累加+1和max宏取最大值来获得最精简的代码。