用SQL删除重复记录的N种方法
发布日期:2022-03-15 04:11:24 浏览次数:62 分类:技术文章

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delete from ItemForScore where ifsid not in (select min(ifsid) from ItemForScore group by itemid,topflag,isactive having COUNT(-1)>1) and itemid in (select itemid from ItemForScore group by itemid having COUNT(-1)>1)
例如:    id           name         value    1               a                 pp    2               a                 pp    3               b                 iii    4               b                 pp    5               b                 pp    6               c                 pp    7               c                 pp    8               c                 iii    id是主键    要求得到这样的结果    id           name         value    1               a                 pp    3               b                 iii    4               b                 pp    6               c                 pp    8               c                 iii 方法1delete   YourTable     where   [id]   not   in   (    select   max([id])   from   YourTable     group   by   (name   +   value))   方法2delete   a    from   表   a   left   join(    select   id=min(id)   from   表   group   by   name,value    )b   on   a.id=b.id    where   b.id   is   null     查询及删除重复记录的SQL语句查询及删除重复记录的SQL语句1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断select * from peoplewhere peopleId in (select   peopleId from   people group by   peopleId having count(peopleId) > 1)2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录delete from peoplewhere peopleId in (select   peopleId from people group by   peopleId   having count(peopleId) > 1)and rowid not in (select min(rowid) from   people group by peopleId having count(peopleId )>1)3、查找表中多余的重复记录(多个字段)select * from vitae awhere (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录delete from vitae awhere (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录select * from vitae awhere (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)(二)比方说在A表中存在一个字段“name”,而且不同记录之间的“name”值有可能会相同,现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;Select Name,Count(*) From A Group By Name Having Count(*) > 1如果还查性别也相同大则如下:Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1(三)方法一declare @max integer,@id integerdeclare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >; 1open cur_rowsfetch cur_rows into @id,@maxwhile @@fetch_status=0beginselect @max = @max -1set rowcount @maxdelete from 表名 where 主字段 = @idfetch cur_rows into @id,@maxendclose cur_rowsset rowcount 0 方法二"重复记录"有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重复的记录,比如Name字段重复,而其他字段不一定重复或都重复可以忽略。  1、对于第一种重复,比较容易解决,使用select distinct * from tableName  就可以得到无重复记录的结果集。  如果该表需要删除重复的记录(重复记录保留1条),可以按以下方法删除select distinct * into #Tmp from tableNamedrop table tableNameselect * into tableName from #Tmpdrop table #Tmp  发生这种重复的原因是表设计不周产生的,增加唯一索引列即可解决。  2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下  假设有重复的字段为Name,Address,要求得到这两个字段唯一的结果集select identity(int,1,1) as autoID, * into #Tmp from tableNameselect min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoIDselect * from #Tmp where autoID in(select autoID from #tmp2)  最后一个select即得到了Name,Address不重复的结果集(但多了一个autoID字段,实际写时可以写在select子句中省去此列)(四)查询重复select * from tablename where id in (select id from tablenamegroup by idhaving count(id) > 1)

 

转载于:https://www.cnblogs.com/systemnet123/archive/2013/04/09/3010115.html

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