本文共 584 字，大约阅读时间需要 1 分钟。

# Definition for singly-linked list.# class ListNode:#     def __init__(self, val=0, next=None):#         self.val = val#         self.next = nextclass Solution:    def deleteDuplicates(self, head: ListNode) -> ListNode:        res = ListNode()        p = res        p.next = head        while p.next and p.next.next:            if p.next.val == p.next.next.val:                q = p.next                while q.next and q.val == q.next.val:                    q = q.next                p.next = q.next            else:                p = p.next        return res.next

注意p的位置，不能到重复的数字