Android 几何图形工具类GeometryUtil
发布日期:2021-06-30 22:37:36 浏览次数:2 分类:技术文章

本文共 2282 字,大约阅读时间需要 7 分钟。

package com.android.imooc.goo;import android.graphics.PointF;/** * 几何图形工具 */public class GeometryUtil {
/** * As meaning of method name. 获得两点之间的距离 * * @param p0 * @param p1 * @return */ public static float getDistanceBetween2Points(PointF p0, PointF p1) { float distance = (float) Math.sqrt(Math.pow(p0.y - p1.y, 2) + Math.pow(p0.x - p1.x, 2)); return distance; } /** * Get middle point between p1 and p2. 获得两点连线的中点 * * @param p1 * @param p2 * @return */ public static PointF getMiddlePoint(PointF p1, PointF p2) { return new PointF((p1.x + p2.x) / 2.0f, (p1.y + p2.y) / 2.0f); } /** * Get point between p1 and p2 by percent. 根据百分比获取两点之间的某个点坐标 * * @param p1 * @param p2 * @param percent * @return */ public static PointF getPointByPercent(PointF p1, PointF p2, float percent) { return new PointF(evaluateValue(percent, p1.x, p2.x), evaluateValue(percent, p1.y, p2.y)); } /** * 根据分度值,计算从start到end中,fraction位置的值。fraction范围为0 -> 1 * * @param fraction * @param start * @param end * @return */ public static float evaluateValue(float fraction, Number start, Number end) { return start.floatValue() + (end.floatValue() - start.floatValue()) * fraction; } /** * Get the point of intersection between circle and line. 获取 * 通过指定圆心,斜率为lineK的直线与圆的交点。 * * @param pMiddle * The circle center point. * @param radius * The circle radius. * @param lineK * The slope of line which cross the pMiddle. * @return */ public static PointF[] getIntersectionPoints(PointF pMiddle, float radius, Double lineK) { PointF[] points = new PointF[2]; float radian, xOffset = 0, yOffset = 0; if (lineK != null) { radian = (float) Math.atan(lineK); xOffset = (float) (Math.sin(radian) * radius); yOffset = (float) (Math.cos(radian) * radius); } else { xOffset = radius; yOffset = 0; } points[0] = new PointF(pMiddle.x + xOffset, pMiddle.y - yOffset); points[1] = new PointF(pMiddle.x - xOffset, pMiddle.y + yOffset); return points; }}

转载地址:https://lovoo.blog.csdn.net/article/details/51581704 如侵犯您的版权,请留言回复原文章的地址,我们会给您删除此文章,给您带来不便请您谅解!

上一篇:Android中注解详解,通过注解代替findViewById方法
下一篇:Android 实现蓝牙客户端与服务器端通信

发表评论

最新留言

不错!
[***.144.177.141]2024年04月21日 12时12分59秒