HDOJ 1393 Weird Clock(明白题意就简单了)
发布日期:2021-06-29 13:33:41
浏览次数:2
分类:技术文章
本文共 1874 字,大约阅读时间需要 6 分钟。
Problem Description
A weird clock marked from 0 to 59 has only a minute hand. It won’t move until a special coin is thrown into its box. There are different kinds of coins as your options. However once you make your choice, you cannot use any other kind. There are infinite number of coins of each kind, each marked with a number d ( 1 <= d <= 1000 ), meaning that this coin will make the minute hand move d times clockwise the current time. For example, if the current time is 45, and d = 2. Then the minute hand will move clockwise 90 minutes and will be pointing to 15.Now you are given the initial time s ( 1 <= s <= 59 ) and the coin’s type d. Write a program to find the minimum number of d-coins needed to turn the minute hand back to 0.
Input
There are several tests. Each test occupies a line containing two positive integers s and d.The input is finished by a line containing 0 0.
Output
For each test print in a single line the minimum number of coins needed. If it is impossible to turn the hand back to 0, output “Impossible”.Sample Input
30 1 0 0Sample Output
1明白题意之后就简单了,
思路:一个钟面只有一根分针。对于一个数字d,把钟面上的分针指向的时间s往后拨s的d倍。问给定d,重复这样的操作多少次能回拨到0。若不能则输出Impossible。 注意:此处的s是不断更新的!!!!!!!!!!! 因为钟面只有60分钟,所以最多不会超过60次,直接暴力就可。import java.util.Scanner;public class Main{ public static void main(String[] args) { Scanner sc = new Scanner(System.in); while(sc.hasNext()){ int s= sc.nextInt(); int d = sc.nextInt(); if(s==0&&d==0){ return ; } int num=s; for(int i=1;i<65;i++){ num = (num+(num*d))%60; if(num==0){ System.out.println(i); break; } if(i>63){ System.out.println("Impossible"); break; } } } }}
转载地址:https://chenhx.blog.csdn.net/article/details/51118567 如侵犯您的版权,请留言回复原文章的地址,我们会给您删除此文章,给您带来不便请您谅解!
发表评论
最新留言
留言是一种美德,欢迎回访!
[***.207.175.100]2024年04月25日 11时45分20秒
关于作者
喝酒易醉,品茶养心,人生如梦,品茶悟道,何以解忧?唯有杜康!
-- 愿君每日到此一游!
推荐文章
报表图表样式
2019-04-29
android模板图例
2019-04-29
树莓派网线直连
2019-04-29
复合材料培训(I第七期)
2019-04-29
复合材料生活中的应用
2019-04-29
ABAQUS复合材料(适合小白)
2019-04-29
ABAQUS高级案例解析
2019-04-29
人工智能药物研发
2019-04-29
【超级干货+福利】AIDD最全面的学习教程
2019-04-29
最新通知:AIDD与网络药理学资料大全
2019-04-29
Lammps分子动力学与第一性原理材料模拟及催化
2019-04-29
实习生小白的日常
2019-04-29
实习小白的日常(4)
2019-04-29
微信扫码登录验证PHP代码(不用开放平台)
2019-04-29
CH554E USB单片机 10引脚小封装低成本USB方案
2019-04-29
windows MQTT客户端
2019-04-29
LINUX下挂载(mount)查看树莓派镜像文件
2019-04-29
基于CH568芯片加密SD卡方案
2019-04-29
1元钱的超低成本单芯片USB单片机方案
2019-04-29