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Problem Description

Given a positive integer n, find the positions of all 1’s in its binary representation. The position of the least significant bit is 0.

Example

The positions of 1’s in the binary representation of 13 are 0, 2, 3.

Task

Write a program which for each data set:

reads a positive integer n,

computes the positions of 1’s in the binary representation of n,

writes the result.

Input

The first line of the input contains exactly one positive integer d equal to the number of data sets, 1 <= d <= 10. The data sets follow.

Each data set consists of exactly one line containing exactly one integer n, 1 <= n <= 10^6.

Output

The output should consists of exactly d lines, one line for each data set.

Line i, 1 <= i <= d, should contain increasing sequence of integers separated by single spaces - the positions of 1’s in the binary representation of the i-th input number.

Sample Input

1 13

Sample Output

0 2 3

思路：

就是输入一个数n，n二进制假如为m。 就是输出二进制m这个数的1所在的位数。从小到大输出。 例如：输入13. 13的二进制数是1101； 所以输出为：0 2 3 注意，最后一个数字后面没有接空格。

import java.util.Scanner;public class Main{    public static void main(String[] args) {        Scanner sc = new Scanner(System.in);        int t = sc.nextInt();        while(t-->0){            int n =sc.nextInt();            String nstr = Integer.toString(n, 2);            //System.out.println(nstr);            boolean isOne=true;            for(int i=nstr.length()-1;i>=0;i--){                if(nstr.charAt(i)=='1'){                    if(isOne){                        System.out.print(nstr.length()-1-i);                        isOne=false;                    }else{                        System.out.print(" "+(nstr.length()-1-i));                    }                }            }            System.out.println();        }    }}

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