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Problem Description

Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?

Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.

Note: if year Y is a leap year, then the 1st leap year is year Y.

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow. Each test case contains two positive integers Y and N(1<=N<=10000).

Output

For each test case, you should output the Nth leap year from year Y.

Sample Input

3 2005 25 1855 12 2004 10000

Sample Output

2108 1904 43236

Hint：

We call year Y a leap year only if (Y%4==0 && Y%100!=0) or Y%400==0.

题意就是：输入一个年份year和一个n，求这个year之后的第n个闰年，

如果year是闰年，则算第一个闰年。

直接暴力做，并没有超时。

import java.util.Scanner;public class Main{    public static void main(String[] args) {        Scanner sc = new Scanner(System.in);        int t = sc.nextInt();        while(t-->0){            int year = sc.nextInt();            int n = sc.nextInt();            int nyear = 0;            if((year%4==0&&year%100!=0)|(year%400==0)){                nyear=1;            }//如果year是闰年，nyear就加一            while(nyear

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