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杭电2199Can you solve this equation?

Problem Description

Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100; Now please try your lucky. Input The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10); Output For each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100.

Sample Input

2 100 -4

Sample Output

1.6152 No solution!

这题是二分法查找。直接套模板

#include
   
    #include
    
     double f(double x){    return  8*pow(x,4.0)+7*pow(x,3.0)+2*pow(x,2.0)+3*x+6;}int main(){    int n;    double m, l, ll, ans, mm;    scanf("%d",&n);    while(n--){        scanf("%lf",&m);        l = 0; ll = 100;        if(m >= f(0) && m <= f(100)){
  //外界条件 ；             while(ll-l > 1e-9){
  //精确度 ；                 mm = (ll + l)/2;                double ans = f(mm);                if(ans > m){
  //二分法；                     ll = mm-1e-9;                }                else{                    l = mm+1e-9;                }            }            printf("%.4lf\n",(ll+l)/2);        }        else    printf("No solution!\n");    }    return 0 ;}
    
   

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