我正在通过java 1.6 u_17进行编程,但是我安装了JRE版本6和JRE版本7,那么如何从JDK 1.6运行我的编译程序以仅通过JRE 6运行？

默认情况下,它通过JRE 7运行我的类文件,如何更改此行为？在Windows 7中设置类路径的任何想法,就像我们为JDK所做的那样.

我的命令提示符中显示以下内容

E:\JAVA>javac -version

javac 1.6.0_17

E:\JAVA>java -version

java version "1.7.0_09"

Java(TM) SE Runtime Environment (build 1.7.0_09-b05)

Java HotSpot(TM) Client VM (build 23.5-b02, mixed mode, sharing)

这是我的SET命令,显示Windows 7环境路径

ALLUSERSPROFILE=C:\ProgramData

APPDATA=C:\Users\Administrator\AppData\Roaming

ClassPath=C:\Program Files\Java\jdk1.6.0_17\bin\mysql-connector-java-5.1.5-bin.jar;

CommonProgramFiles=C:\Program Files\Common Files

COMPUTERNAME=RANDMATE-PC

ComSpec=C:\Windows\system32\cmd.exe

FP_NO_HOST_CHECK=NO

HOMEDRIVE=C:

HOMEPATH=\Users\Administrator

JAVA_HOME=C:\Program Files\Java\jre6\bin;

LOCALAPPDATA=C:\Users\Administrator\AppData\Local

LOGONSERVER=\\RANDMATE-PC

NUMBER_OF_PROCESSORS=2

OS=Windows_NT Path=C:\Windows\system32;C:\Windows;C:\Windows\System32\Wbem;C:\Windows\System32\WindowsPowerShell\v1.0\;C:\Program Files\Java\jdk1.6.0_17\bin;C:\Program Files\Java\jre6\bin;C:\Program Files\MyS

QL\MySQL Server 5.1\bin;C:\Program Files\UltraEdit\;C:\Program Files\Jar2Exe Wizard\;C:\Program Files\Java\jre6\bin;

PATHEXT=.COM;.EXE;.BAT;.CMD;.VBS;.VBE;.JS;.JSE;.WSF;.WSH;.MSC

PROCESSOR_ARCHITECTURE=x86

PROCESSOR_IDENTIFIER=x86 Family 15 Model 6 Stepping 5, GenuineIntel

PROCESSOR_LEVEL=15

PROCESSOR_REVISION=0605

ProgramData=C:\ProgramData

ProgramFiles=C:\Program Files

PROMPT=$P$G

PSModulePath=C:\Windows\system32\WindowsPowerShell\v1.0\Modules\

PUBLIC=C:\Users\Public

SESSIONNAME=Console

SystemDrive=C:

SystemRoot=C:\Windows

TEMP=C:\Users\ADMINI~1\AppData\Local\Temp

TMP=C:\Users\ADMINI~1\AppData\Local\Temp

USERDOMAIN=RANDMATE-PC

USERNAME=Administrator

USERPROFILE=C:\Users\Administrator

windir=C:\Windows