本文共 1057 字,大约阅读时间需要 3 分钟。
Given an array of citations (each citation is a non-negative integer) of a researcher, write a function to compute the researcher's h-index.
According to the : "A scientist has index h if h of his/her N papers have at least h citations each, and the other N − h papers have no more than h citations each."
For example, given citations = [3, 0, 6, 1, 5]
, which means the researcher has 5
papers in total and each of them had received 3, 0, 6, 1, 5
citations respectively. Since the researcher has 3
papers with at least 3
citations each and the remaining two with no more than 3
citations each, his h-index is 3
.
Note: If there are several possible values for h
, the maximum one is taken as the h-index.
看完题目,根本不知道说的是什么?
参考:
public class Solution274 { public int hIndex(int[] citations) { int[] hash = new int[citations.length+1]; for(int i=0; icitations.length){ hash[citations.length]++; } else{ hash[citations[i]]++; } } int sum=0; for(int k=citations.length; k>=0; k--){ sum+=hash[k]; if(sum>=k) return k; } return 0; }}
转载地址:https://blog.csdn.net/zxdfc/article/details/48738077 如侵犯您的版权,请留言回复原文章的地址,我们会给您删除此文章,给您带来不便请您谅解!